You're amazing
Or at least 2/3 of the people that help.
It's OK to ask for help in the FM, right? ._.
I only have 15mil now because I spent it on tutoring. ><
You're amazing
Sorry, Donny!
Heheh.
P.S.:
That's just projectile motion!
Constant speed on the x-axis and straight down (g only) on the y-axis!
The guy was wrong, by the way.
Here's the correct solution, I think:
"X = VT" is simply "distance = velocity x time"
Y = V1T + 1/2 GT^2 is one of the kinematic equations.
V1 refers to initial velocity, and since we're using this equation for the y-axis, V1 is 0 (he throws it horizontally, so there's no downward velocity on the ball when he throws it).
Thus Y = 1/2 GT^2
So basically you first convert the 60 ft. into meters (WHICH I DID WRONG in the picture above).
Then, you plug the meter value of the horizontal distance (X) as well as the initial horizontal velocity (V) into X = VT.
You solve for T, and plug in T into Y = 1/2 GT^2.
Since G is a constant (9.8 m/s^2), you can solve for Y, your answer.
The correct answer should be around 0.196m.
OH ****.
I didn't read it carefully.
I thought it said 90 meters/second.
JESUS CHRIST.
Okay, brb. Making new pictar.
thattttssss coool <3_<3 ishuddd try someday =D but maybe ill do it on ppl who i know more. cause sometimes fm ppl scare me =(
~~iRebeKaYx3 Rebecca.Yao RebekaY Rebecca.Yao
... Rebecca.Yao RebekaY Rebecca.YaoRebecca.Yao RebekaY Rebecca.Yao Scania LilKawaiiie<3
Guilds<3~
iChocoLate
HiddenStreet
AmbienceY
OKAY HERE
THIS IS TEH RITE 1
Explanation:
"X = VT" is simply "distance = velocity x time"
Y = V1T + 1/2 GT^2 is one of the kinematic equations.
V1 refers to initial velocity, and since we're using this equation for the y-axis, V1 is 0 (he throws it horizontally, so there's no downward velocity on the ball when he throws it).
Thus Y = 1/2 GT^2
So basically you first convert the 60 ft. into meters and the 90 mph into meters/second.
Then, you plug the meter value of the horizontal distance (X) as well as the initial horizontal velocity (V) into X = VT.
You solve for T, and plug in T into Y = 1/2 GT^2.
Since G is a constant (9.8 m/s^2), you can solve for Y, your answer.
The correct answer should be 2.227272727272727272727..........
I told you to use basick maf skillz but nuuuuuuuuuuu you just had to go about it the right way.
(Scania)
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