Why the hell would anyone get any other flavor then Chocolate-Chocolate-Chocolate?
stupidmathquestionisstupid
if there are 9 ice cream flavors, and you can choose 3 from it to make a triple scoop combo, how many combinations are possible if you can get the same flavor twice or more? By the way, it says to use the nCr formula, not the nPr, because I am trying to get the COMBINATIONS, not the PERMUTATIONS.
Help??
By the way, it can be like Chocolate-Chocolate-Chocolate.
Why the hell would anyone get any other flavor then Chocolate-Chocolate-Chocolate?
stupidmathquestionisstupid
Hello azn4anime! It appears that you have not posted in our forum in several weeks, why not take a few moments to ask a question in our various boards, help answer your fellow Maplers' questions with your knowledge, or just engage in a conversation with another member in any one of our boards?
im gonna guess 729, just cause 9x9x9= 729, and im basing this off the fact that for each one you can have 9 different flavors, meaning say we number the flavors, it can be like this
1,1-9,1-9
2,1-9,1-9....
....
though if that true i have no idea, and i dont think thats how you want me to solve it.
My Blag
P.S. i cant spell
Easy.
9 nCr 3
=/
Combinations mean that the order of choices don't matter, and permutations is where the order matters (so 123 is different from 213).
I put it in my calculator, and it's 84.
Lore, you're wrong, because 9^3 would suggest that the order of the choices matters, which it does not.
[/data management]
bolt202/veil225/feint200
knew i was wrong, thanks for explaining why though, i do not enjoy math
My Blag
P.S. i cant spell
i dont think 9^3 makes the order. it just gives all possiblities.
if he did something like 9x8x7 then something like that would suggest you cant choose the same flavor but in this case you can.
so you get nine choices three times.
i dont know how your calculator even got 84 though.
but what can i say i havent done this in a long time xP
btw a4a youre wrong, its vanilla-vanilla-vanilla
Zig here's how: nCr=n!/((n-r)!(r!)
Let n=9, and r=3. Voila.
What class is this again?
No more sig. Thinking.
Err, it might be stats. But I remember learning this in Algebra 2.